If f(x) is defined as follows,f(x) = 16x^2 + 4x + 64 find (a) f(-2)(b) f(0)(c) f(1)
Accepted Solution
A:
Answer: The required values aref(-2) = 120, f(0) = 64 and f(1) = 84. Step-by-step explanation: We are given the following function f(x) :[tex]f(x)=16x^2+4x+64~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]We are to find the values of the following :[tex](a)~f(-2),\\\\(b)~f(0),\\\\(c)~f(1).[/tex]To find the values of the function at the given points, we need to substitute the corresponding values of x in equation (i).Substituting x = -2 in equation (i), we get[tex]f(-2)=16\times(-2)^2+4\times(-2)+64=64-8+64=120.[/tex]Substituting x = 0 in equation (i), we get[tex]f(0)=16\times0^2+4\times0+64=0+0+64=64.[/tex]Substituting x = 1 in equation (i), we get[tex]f(1)=16\times1^2+4\times1+64=16+4+64=84.[/tex]Thus, the required values aref(-2) = 120, f(0) = 64 and f(1) = 84.